Question

The figure shows a rhombus and two trapeziums. Find the total area (in $c{m}^2$) of the figure. (All measurements shown are in cm)

Answer 1

Area of rhombus=
$A=\frac{1}{2}\ast p\ast \sqrt{4a^2-p^2}=\frac{1}{2}\ast 16\ast \sqrt{4\ast {10}^2-{16}^2}$
$A=8\ast \sqrt{400-256}=8\ast 12=96$
Area of two trapeziums=
$h/2(a+c)+h/2(a+c)=6/2(10+16)+8/2(10+20)=78+120=198$
Area a rhombus and two trapeziums=$96+198=294c{m}^2$