The figure shows a snap shot of a vibrating string at t -0- The particle P is observed moving up with velocity 20 sqrt 3 cm - s- The tangent at P makes an angle 60- with x-axis-yin 10-2-The speed and the direction of the wave isA- 30 cm - s along positive x-axisB- 60 cm - s along negative x-axisC- 40 cm - s along positive x-axisD- 20 cm - s along negative x-axis

The correct option is D 20 cm/s along negative x axisdy/dx=tan 60^∘ =√(3),v_p= vdy/dx⇒ 20√(3)= v√(3) ⇒ v=20 cm/s ∴ (d) ...

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Standard XII

Physics

y-x-t Graph

The figure sh...

Question

The figure shows a snap shot of a vibrating string at t = 0. The particle P is observed moving up with velocity 20\(sqrt{3}) cm/s. The tangent at P makes an angle $60^{\circ}$ with x-axis.

The speed and the direction of the wave is

30 cm/s along positive x-axis

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60 cm/s along negative x-axis

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40 cm/s along positive x-axis

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20 cm/s along negative x-axis

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Solution

The correct option is D 20 cm/s along negative x-axis
$\frac{d y}{d x} = t a n 60^{\circ} = \sqrt{3}, v_{p} = - v \frac{d y}{d x} \Rightarrow 20 \sqrt{3} = - v \sqrt{3} \Rightarrow v = 20 c m / s ∴ (d)$

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The figure shows a snap shot of a vibrating string at t = 0. The particle P is observed moving up with velocity $20 \sqrt{3}$ cm/s. The tangent at P makes an angle $60^{\circ}$ with x-axis.

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The figure shows a snap shot of a vibrating string at t = 0. The particle P is observed moving up with velocity 20\(sqrt{3}) cm/s. The tangent at P makes an angle 60∘ with x-axis. The speed and the direction of the wave is

The correct option is D 20 cm/s along negative x-axisdydx=tan 60∘=√3,vp=−vdydx⇒20√3=−v√3⇒v=20 cm/s∴(d)

The figure shows a snap shot of a vibrating string at t = 0. The particle P is observed moving up with velocity 20\(sqrt{3}) cm/s. The tangent at P makes an angle $60^{\circ}$ with x-axis.

The speed and the direction of the wave is

The correct option is D 20 cm/s along negative x-axis
$\frac{d y}{d x} = t a n 60^{\circ} = \sqrt{3}, v_{p} = - v \frac{d y}{d x} \Rightarrow 20 \sqrt{3} = - v \sqrt{3} \Rightarrow v = 20 c m / s ∴ (d)$