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Question

# The figure shows a solenoid carrying time varying current I=I0t. On the axis of this solenoid a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self inductance of the ring is L. If the resistance of the ring is R then the maximum current which can flow through the ring is equal to

A
(2M+L)I0R
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B
MI0R
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C
(2ML)I0R
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D
(M+L)I0R
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Solution

## The correct option is B MI0RThe flux linked with the ring due to solenoid is MI ϕ=MI=MI0t Only mutual inductance will play a role as there is no factor affecting the self inductance. Hence e=dϕdt=MI0 Current I=eR=MI0R Hence option (B) is correct.

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