The figure shows a solid of uniform cross section. Find the volume of the solid. It is being given that all the measurements are in $c m$ and each angle in the figure is a right angle
(Hint: This consists of two cuboids of dimensions
[ $(4 \times 6 \times 3) {c m}^{3}$ and $(4 \times 3 \times 9) {c m}^{3}$ ]

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Solution

Total volume
$=$ vol of $(1)$ $+$ vol of $(2)$

$= (9 \times 3 \times 4)$ $+ (6 \times 3 \times 4)$

$= 108 + 72$

$= 180 c m^{3}$

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The figure shows a solid of uniform cross section. Find the volume of the solid. It is being given that all the measurements are in cm and each angle in the figure is a right angle(Hint: This consists of two cuboids of dimensions[(4×6×3)cm3 and (4×3×9)cm3]

Total volume = vol of (1) + vol of (2)=(9×3×4)+(6×3×4)=108+72=180cm3

Total volume
$=$ vol of $(1)$ $+$ vol of $(2)$

$= (9 \times 3 \times 4)$ $+ (6 \times 3 \times 4)$

$= 108 + 72$

$= 180 c m^{3}$