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Standard X

Physics

Magnetic Field Due to a Straight Current Carrying Conductor

The figure sh...

Question

The figure shows a wire sliding on two parallel conducting rails placed at a separation l. A magnetic field B exists in a direction perpendicular to the plane of the rails. The force required to keep the wire moving at a Constant velocity v will be:

e v B

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\frac{μ_{0} B v}{4 π l}

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B l v

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zero

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Solution

The correct option is A zero
Give:
Magnetic field $B$
Rod separated by $L$
According to question, Loop is not close So EMF will induce in the rod but current will not flow.
$∴$ Force $F = B I L = 0$
Option D

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The figure shows a wire sliding on two parallel conducting rails placed at a separation l. A magnetic field B exists in a direction perpendicular to the plane of the rails. The force required to keep the wire moving at a Constant velocity v will be:

The correct option is A zeroGive:Magnetic field BRod separated by LAccording to question, Loop is not close So EMF will induce in the rod but current will not flow.∴ Force F=BIL=0Option D

The correct option is A zero
Give:
Magnetic field $B$
Rod separated by $L$
According to question, Loop is not close So EMF will induce in the rod but current will not flow.
$∴$ Force $F = B I L = 0$
Option D