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Question

The figure shows cross section of a hollow glass tube of internal radius r, external radius R and index of refraction n. For two rays DE and ABC (in which DE lies on ODE and DE is parallel to BC), the separation r1 will be :
127107_9adcb219a1214d05b582f10bf0c70035.png

A
r1=(n1)R
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B
r1=n2R
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C
r1=nr
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D
r1=n2r
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Solution

The correct option is D r1=nr


In given figure θ is angle of refraction and α is angle of incidence for ray ABC.

Required length = r1=BP

Since DEBCBOP=θ

Now, in ΔBOP:

r1=BP=OBsinθ=Rsinθ

sinθ=r1R

In ΔOAB:
A=90o
sinα=rR

Now, at refraction of ray ABC

sinθsinα=n

r1/Rr/R=nr1r=n

r1=nr

Answer-(C)

834455_127107_ans_7b0fe52f19964820890f2e463cf311e6.png

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