The figure shows four wire loops, with edge lengths of either $L o r 2 L$ . All four loops will move through a region of uniform magnetic field $\to B$ (directed out of the page) at the same constant velocity. Rank the four loops according to the maximum magnitude of the e.m.f. $(e)$ induced as they enter the field.

$(e_{c} = e_{d}) < (e_{a} = e_{b})$

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$(e_{c} = e_{d}) > (e_{a} = e_{b})$

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$e_{c} > e_{d} > e_{b} > e_{a}$

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$e_{c} < e_{d} < e_{b} < e_{a}$

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Solution

The correct option is B
$(e_{c} = e_{d}) > (e_{a} = e_{b})$

Emf induces across the length of the wire which cuts the magnetic field.
(Length of c = Length d) > (Length of a = b).
So
$(e_{c} = e_{d}) > (e_{a} = e_{b})$

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The correct option is B (ec=ed)>(ea=eb) Emf induces across the length of the wire which cuts the magnetic field. (Length of c = Length d) > (Length of a = b). So (ec=ed)>(ea=eb)

The correct option is B
$(e_{c} = e_{d}) > (e_{a} = e_{b})$

Emf induces across the length of the wire which cuts the magnetic field.
(Length of c = Length d) > (Length of a = b).
So
$(e_{c} = e_{d}) > (e_{a} = e_{b})$