The figure shows one end of a string being pulled down at constant velocity v. Find the velocity of mass 'm' as a function of 'x'?
A
−v2x√x2+b2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
−v2x√x2−b2
No worries! Weโve got your back. Try BYJUโS free classes today!
C
v2x√x2+b2
No worries! Weโve got your back. Try BYJUโS free classes today!
D
v2x√x2−b2
No worries! Weโve got your back. Try BYJUโS free classes today!
Open in App
Solution
The correct option is A−v2x√x2+b2 Using constraint equation 2√x2+b2+y = length of string = constant. 22√x2+b2⋅2x(dxdt)+(dydt)=0 ⇒(dydt)=v(dxdt)=−v2x√x2+b2