The figure shows part of a bigger circuit. At the moment, the capacity of the capacitor is 6μF and decreasing at the constant rate 0.5μFs–1. The potential difference across the capacitor at this moment is changing as under [direction of current is shown in figure] dVdt=2Vs−1, d2Vdt2=12Vs−2
The current in the 4ω resistor is decreasing at the rate of 1μAs−1 What is the potential difference (in micro volts) across the inductor at this moment ?
VL=∣∣∣diRdt−d2qdt2∣∣∣=L∣∣ddtiR−(Cd2Vdt2+2dCdtdVdt)∣∣ =8volts.