The figure shows that O is the centre of the circle and XOY is a diameter. If XZ is any other chord of the circle, then

XY > XZ

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XY = XZ

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XY < XZ

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XY = OZ

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Solution

The correct option is A
XY > XZ

In ΔXOZ, XO + OZ >XZ (sum of two sides of a triangle is greater than the third side)

Or XO + OY > XZ (OY = OZ radii of the circle)

XY > XZ

Suggest Corrections

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