wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

The figure shows the cross-section of the outer wall of a house built in a hill - resort to keep the house insulated from the freezing temperature of outside. The wall consists of teak wood of thickness L1 and brick of thickness (L=5L1). sandwiching two layers of an unknown material with identical thermal conductivities and thickness. The thermal conductivity of teak wood is K1 and that of brick is (K2=5K). Heat conduction through the wall has reached a steady-state with the temperature of three surfaces being known. (T1=25C,T2=20C and T5=20C). Find the interface temperature T4 and T3.

300632_387439f47e8e4eb4b2668a1018936066.png

A
2.5o
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
7o
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.5o
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
9o
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2.5o
Let interface area be A. then thermal resistance of wood,
R1=L1K1A
and that of brick wall
R2=L2K2A=5L15K1A=R1
Let thermal resistance of the each sand witch layer = R. Then the above wall can be visualised as a circuit
thermal current through each wall is same.
Hence 2520R1=20T3R=T3T4R=T4+20R1
2520=T4+20
T4=15C
Also, 20T3=T3T4
T3=20+T42=2.5C

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Work Done
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon