The figure shows the displacement time graph of a particle moving on a straight line path. What is the magnitude of average velocity of the particle over 10 s?

2 m s^{- 1}

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4 m s^{- 1}

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6 m s^{- 1}

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8 m s^{- 1}

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Solution

The correct option is A $2 m s^{- 1}$
Net displacement of the particle in 10 s, $S = B C - O A = 40 - 60 = - 20$ m
Total time taken $t = 10$ s
$∴$ Average velocity of the particle $v_{a v g} = \frac{S}{t} = \frac{- 20}{10} = - 2 m / s$
Thus magnitude of average velocity of the particle is $2 m / s$ .

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