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Standard XII

Physics

TIR

The figure sh...

Question

The figure shows the face and interface temperatures of a composite slab consisting of four layers of two materials having identical thickness. Under steady state condition, find the value of temperature $θ$ in $^{o} C$ :

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Solution

Since $\frac{Q}{t} = K A \frac{d T}{d x}$
In steady state, same heat will pass
$2 K \frac{(10 - θ)}{Δ x} = K \frac{(θ - (- 5))}{Δ x}$
$∴ 3 θ = 15$
$∴ θ = 5^{0} C$

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The figure shows the face and interface temperatures of a composite slab consisting of four layers of two materials having identical thickness. Under steady state condition, find the value of temperature θ in oC :

Since Qt=KAdTdxIn steady state, same heat will pass 2K(10−θ)Δx=K(θ−(−5))Δx∴3θ=15∴θ=50C

The figure shows the face and interface temperatures of a composite slab consisting of four layers of two materials having identical thickness. Under steady state condition, find the value of temperature $θ$ in $^{o} C$ :

Since $\frac{Q}{t} = K A \frac{d T}{d x}$
In steady state, same heat will pass
$2 K \frac{(10 - θ)}{Δ x} = K \frac{(θ - (- 5))}{Δ x}$
$∴ 3 θ = 15$
$∴ θ = 5^{0} C$