Question

The figure shows the force versus time graph for a particle. Then

• A. Change in momentum of the particle is $20\text{N-s}$
• B. Average force acting on the particle is $50\text{N}$
• C. Change in momentum of the particle is $50\text{N-s}$
• D. Average force acting on the particle is $20\text{N}$

Answer 1

Answer: (A), (B)

Average force acting on the particle is $50\text{N}$

Area under $F-t$ curve is change in momentum
$\Delta p=\frac{1}{2}\times 0.4\times 100=20\text{N-s}$
As
$\Delta p=F_{\text{avg.}}\Delta t$
$\therefore$ average force $=\frac{20}{0.4}=50\text{N}$