The figure shows the graph of logarithmic reading of pressure and volume for two ideal gases A and B undergoing adiabatic process. From figure it can be concluded that
A
gas B is diatomic
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B
gas A and B both are diatomic
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C
gas A is monoatomic
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D
gas B is monoatomic & gas A is diatomic
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Solution
The correct option is D gas B is monoatomic & gas A is diatomic The figure shows the graph of logarithmic reading of pressure and volume for two ideal gases A and B undergoing adiabatic process. From figure it can be concluded that gas B is monoatomic & gas A is diatomic. The slope of both the gases is negative. The slope for B is much more negative than the slope for A.