The figure shows the position time graph of a particle of mass $40 k g$ . What is the force acting on the particle for $0 < t < 4 s$

30 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

z e r o

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

53.33 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $z e r o$
At t = 0 s
m = 4 kg
u = 0
v = 3/4 m/s
∴ Impulse = 4(3/4–0) = 3 kgm/s
At t = 4 s
m = 4 kg
u = 3/4 m/s
v = 0
∴ Impulse = 4(0–3/4) = -3 kgm/s.
Force = Change in impulse = 3+(-3) = 0
Hence option (B) is correct

Suggest Corrections

Similar questions

Figure 5.16 shows the position-time graph of a particle of mass 4 kg. What is the (a) force on the particle for $t < 0, t > 4 s, 0 < t < 4 s$ ?
(b) impulse at t = 0 and t = 4 s?
(Consider one-dimensional motion only).

Q. Figure shows the position-time graph of a particle of mass

4 k g

. What is the (a) force on the particle for

t < 0, t > 4 s, 0 < t < 4 s

(b) impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only).

Figure 5.16 shows the position-time graph of a particle of mass 4 kg. What is the (a) force on the particle for t < 0, t > 4 s, 0 < t < 4 s? (b) impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only).

Figure 5.16

Q. The position (x) - time (t) graph for a particle of mass

1 k g

moving along x-axis is shown in figure. Find impulse on particle at

t = 4 s

Q. Figure shows the position-time graph of a particle of mass 4 kg. Let the force on the particle for t < 0,0<t<4,0 < 4 s, be

F_{1}, F_{2}

and

F_{3}

respectively. Then

Join BYJU'S Learning Program

The figure shows the position time graph of a particle of mass 40 kg. What is the force acting on the particle for 0<t<4s

The correct option is B zero At t = 0 sm = 4 kgu = 0v = 3/4 m/s∴ Impulse = 4(3/4–0) = 3 kgm/sAt t = 4 sm = 4 kgu = 3/4 m/sv = 0∴ Impulse = 4(0–3/4) = -3 kgm/s.Force = Change in impulse = 3+(-3) = 0Hence option (B) is correct

The figure shows the position time graph of a particle of mass $40 k g$ . What is the force acting on the particle for $0 < t < 4 s$

The correct option is B $z e r o$
At t = 0 s
m = 4 kg
u = 0
v = 3/4 m/s
∴ Impulse = 4(3/4–0) = 3 kgm/s
At t = 4 s
m = 4 kg
u = 3/4 m/s
v = 0
∴ Impulse = 4(0–3/4) = -3 kgm/s.
Force = Change in impulse = 3+(-3) = 0
Hence option (B) is correct