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Question

The figure shows the variation of photo current with anode potential for a photo-sensitive surface for three different radiations. Let Ia,Iband Ic and be the intensities and υa,υbandυc be the frequencies for the curves a, b and c respectively. Then :

942619_482004503cc34567a33be6bbd7782e09.png

A
υa=υbandIaIb
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B
υa>υcandIaIc
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C
υa<υbandIaIb
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D
υb=υcandIbIc
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Solution

The correct option is B υa=υbandIaIb
From the graph, we note that the saturation current is same for curves b and c but different for curve a. Therefore, intensities of b and c will be equal but different from that of a i.e. IaIb but Ib=Ic. As stopping potential is same for curves a and b, hence υa=υb. Thus answer (a) is correct.
1098944_942619_ans_b39a715ee78947648964a59eeb5f8ec6.png

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