Question

The figure shows the velocity and acceleration of a point like body at the initial moment of its motion. The acceleration vector of the body remains constant. The minimum radius of curvature of trajectory of the body is (in $\text{m}$ upto two decimals.)

Answer 1

$r=\frac{v^2}{a_n}$
Radius of curvature $r_{\text{min}}$ means $v$ is minimum and $a_n$ is maximum.
This is at point $P$ when component of velocity parallel to acceleration vector becomes zero, that is $u_B=0$.

$R=\frac{u_{\perp }^2}{a}=\frac{4^2}{2}=8\text{meters}$.