The figure shows two large, closely placed, parallel, nonconducting sheets with identical (positive) uniform surface charge densities, and a sphere with a uniform (positive) volume charge density. Four points marked as 1, 2, 3 and 4 are shown with in the space in between. If $E_{1}, E_{2}, E_{3}$ and $E_{4}$ are magnitude of net electric field at these points respectively then:

E_{1} > E_{2} > E_{3} > E_{4}

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E_{1} > E_{2} > E_{3} = E_{4}

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E_{3} = E_{4} > E_{2} > E_{1}

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E_{1} = E_{2} = E_{3} = E_{4}

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Solution

The correct option is C $E_{3} = E_{4} > E_{2} > E_{1}$
Electric field due to one plate $= \frac{σ}{ε_{o}}$
Due to other $= \frac{σ}{ε_{o}}$
since, they are equal in magnitude and in opposite direction they cancel each other.
Thus sole electric field is due to spherical charge,
Thus,
$\begin{matrix} E α \frac{1}{r^{2}} ∴ E_{3} = E_{4} > E_{2} > E_{1} H e n c e, o p t i o n C i s t h e c o r r e c t a n s w e r . \end{matrix}$

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The correct option is C E3=E4>E2>E1Electric field due to one plate =σεoDue to other =σεosince, they are equal in magnitude and in opposite direction they cancel each other.Thus sole electric field is due to spherical charge,Thus,Eα1r2∴E3=E4>E2>E1Hence,optionCisthecorrectanswer.