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Question

The figure shows two similar capacitors connected to a battery. Initially, switch was closed and when opened, the capacitors were filled with a dielectric of dielectric constant 3. The potential difference across capacitor B is:
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A
6 V
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B
3 V
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C
32 V
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D
2 V
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Solution

The correct option is D 2 V
When switch is closed, both the capacitors are in parallel.
Charge on both capacitors: qA=qB=CV=6C
When switch is opened, the capacitance of each capacitor becomes C=KC=3C
Now potential difference across B is: VB=qBC=6C3C=2 Volt

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