Question

The figure shows $v-t$ graph for various situations. What does that graph indicates

• A. $OA\to \text{increasing acceleration.}BC\to \text{constant positive acceleration}$
• B. $OA\to \text{decreasing acceleration.}BC\to \text{constant positive acceleration}$
• C. $OA\to \text{decreasing acceleration.}BC\to \text{constant negative acceleration}$
• D. $OA\to \text{increasing acceleration.}BC\to \text{constant negative acceleration}$

Answer 1

The correct option is C $OA\to \text{decreasing acceleration.}BC\to \text{constant negative acceleration}$

We know,

Acceleration is nothing but slope of v-t graph.

In $OA$

The slope is initially acute, and finally zero,

Hence acceleration decreases in $OA$

In $CB$,

The slope angle is obtuse and hence slope is negative,

And so is the acceleration.

Option $\text{C}$ is the correct answer