The final product formed when ethyl bromide is treated with excess of alcoholic KOH is

Ethylene

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Ethane

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Ethyne

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Vinyl bromide

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Solution

The correct option is A Ethylene
$C H_{3} - C H_{2} - B r + K O H \to C H_{2} = C H_{2} + K B r + H_{2} O$

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The final product formed when ethyl bromide reacts with excess of alcoholic KOH

A g_{2} O,

A g_{2} O

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