The final product is formed followed by the formation of _______ carbocation.
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Solution
The pi electrons of carbon-carbon double bond are donated to proton to form a secondary carbocation.
The less stable secondary carbocation rearranges to more stable tertiary carbocation by 1,2-methyl shift.
Nucleophilic attack of water molecule followed by deprotonation forms the product. In this reaction, a molecule of water is added to a carbon-carbon double bond.