The final product IV obtained in the reaction sequence -Toluene I SOC l 2 - II N H 3 - III OBr - - IVis -

The correct option is D C _ 6 H _ 5 NH _ 2 C_6H_5CH_3C_6H_5COOHC_6H_5COClC_6H_5CONH_2C_6H_5NH_2 First, Toluene undergoes oxidation to form benzoic ...

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Byju's Answer

Standard XII

Chemistry

Curtius and Hofmann Rearrangements

The final pro...

Question

The final product (IV) obtained in the reaction sequence :
Toluene ${2. H}^{+} - --------- \to 1. K M n O_{4} / {O H}^{-} I S O C l_{2} ⟶ I I N H_{3} ⟶ I I I^{-} I V$
is :

C_{6} H_{5} {C O N H}_{2}

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P - {{C H}_{3} C}_{6} H_{4} {N O}_{2}

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C_{6} H_{5} {C H}_{2} {N H}_{2}

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C_{6} H_{5} {N H}_{2}

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Solution

The correct option is D $C_{6} H_{5} {N H}_{2}$
$C_{6} H_{5} C H_{3} K M n O_{4} / O H^{-} - -------- \to 2 H^{+} C_{6} H_{5} C O O H S O C l_{2} - --- \to C_{6} H_{5} C O C l N H_{3} - -- \to C_{6} H_{5} C O N H_{2} O B r^{-} - -- \to C_{6} H_{5} N H_{2}$

First, Toluene undergoes oxidation to form benzoic acid which on reaction with $S O C l_{2}$ forms benzoyl chloride.

This benzoyl chloride reacts with $N H_{3}$ to form the corresponding amide.

This amide on reaction with (hoffmann bromamide) $O B r^{-}$ forms Aniline as a product.-

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Similar questions

Q. Arrange the following in the decreasing order of basic strength:
i)

C_{6} H_{5} {N H}_{2}

ii)

C_{6} H_{5} {N H C H}_{3}

iii)

C_{6} H_{5} {C H}_{2} {N H}_{2}

Q. Arrange the following in the increasing order of basic strength:
i)

C_{6} H_{5} {N H}_{2}

ii)

C_{6} H_{5} {N H C H}_{3}

iii)

C_{6} H_{5} {C H}_{2} {N H}_{2}

Q. Arrange the following in the increasing order of their basic strength.

{C H}_{3} {N H}_{2}, {({C H}_{3})}_{2} N H, C_{6} H_{5} {N H}_{2}, C_{6} H_{5} {C H}_{2} {N H}_{2}

Q. Arrange the following in the increasing order of the

{p K}_{b}

values:

C_{2} H_{5} N H_{2}

ii)

C_{6} H_{5} {N H C H}_{3}

iii)

(C_{2} H_{5})_{2} N H

iv)

C_{6} H_{5} {N H}_{2}

Q. IUPAC name of

C_{6} H_{5} - {C H}_{2} - {C H}_{2} - {N H}_{2}

is :

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The final product (IV) obtained in the reaction sequence :Toluene 2.H+−−−−−−−−−−→1.KMnO4/OH−ISOCl2⟶IINH3⟶IIIOBr−⟶IVis :

The final product (IV) obtained in the reaction sequence :
Toluene ${2. H}^{+} - --------- \to 1. K M n O_{4} / {O H}^{-} I S O C l_{2} ⟶ I I N H_{3} ⟶ I I I^{-} I V$
is :