wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The final product (IV) obtained in the reaction sequence :
Toluene 2.H+−−−−−−−−−1.KMnO4/OHISOCl2IINH3IIIOBrIV
is :

A
C6H5CONH2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
PCH3C6H4NO2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
C6H5CH2NH2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
C6H5NH2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D C6H5NH2
C6H5CH3KMnO4/OH−−−−−−−−2H+C6H5COOHSOCl2−−−C6H5COClNH3−−C6H5CONH2OBr−−C6H5NH2

First, Toluene undergoes oxidation to form benzoic acid which on reaction with SOCl2 forms benzoyl chloride.

This benzoyl chloride reacts with NH3 to form the corresponding amide.

This amide on reaction with (hoffmann bromamide) OBr forms Aniline as a product.-

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Preparation of Amines
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon