The final product of chlorination of methane in the sun light is ?

C H_{3} C_{1}

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C H_{2} C l_{2}

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C H C I_{3}

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C C I_{4}

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Solution

The correct option is D $C C I_{4}$
Chlorination of methane follows free radial mechanism. When chlorine is present in small quantity then only single substitution takes place, but if chlorine is present in excess then all the hydrogen is substituted by chlorine. So tetra substituted product is formed. The following is the reaction of chlorination of methane:

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