The final products formed when acetylene reacts with $H C N$ & $C H_{3} C O O H$ separately,respectively are :

C H_{3} - C H (C N)_{2}

C H_{3} - C H (O C O C H_{3})_{2}

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C H_{3} - C H (C N)_{2}

C H_{2} = C H (O C O C H_{3})

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C H_{2} = C H C N

C H_{3} - C H (O C O C H_{3})_{2}

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C H_{2} = C H C N

C H_{2} = C H (O C O C H_{3})

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Solution

The correct option is A $C H_{3} - C H (C N)_{2}$ & $C H_{3} - C H (O C O C H_{3})_{2}$
$H - C \equiv C A c e t y l e n e - H H C N - ----- \to C u_{2} (C N)_{2} C H_{2} = C H - C N (V i n y l C y a n i d e)$ $- -- \to H C N C H_{3} - C H (C N)_{2}$

$H - C \equiv C A c e t y l e n e - H C H_{3} C O O H - ------ \to H g^{2 +} H_{2} C = C H - (O C O C H_{3})$
$C H_{3} C O O H - ------ \to H G^{2 +} C H_{3} - C H (O C O C H_{3})_{2}$
Ethylidine acetate

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