The final step for the extraction of copper from copper pyrites in Bessemer converter the reaction involves is as:

C u_{2} S + 2 F e O ⟶ 2 C u + 2 F e + S O_{2}

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C u_{2} S + 2 C u O ⟶ 6 C u + S O_{2}

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4 C u_{2} S + F e S ⟶ 8 C u + 2 F e S O_{4}

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2 C u_{2} O + F e S ⟶ 4 C u + 2 F e + S O_{2}

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Solution

The correct option is B $C u_{2} S + 2 C u O ⟶ 6 C u + S O_{2}$
The final step for the extraction of copper from copper pyrites in Bessemer converter the reaction involves is as $C u_{2} S + 2 C u O ⟶ 6 C u + S O_{2}$ .
This reaction represents auto reduction. $C u_{2} O$ reacts with $C u_{2} S$ to give copper metal. The solid metal obtained is called as blister copper and is about 99% pure.

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Similar questions

C u_{2} S + 2 C u_{2} O \to 6 C u + S o_{2}

A : F e O + S i O_{2} \to F e S i O_{3}

B : 2 F e S + 3 O_{2} \to 2 F e O + 2 S O_{2}

C : 2 C u_{2} S + 3 O_{2} \to 2 C u_{2} O + 2 S O_{2}

D : 2 C u_{2} O + C u_{2} S \to 6 C u + S O_{2}

Select reactions actually taking place :

2 C u F e S_{2} + O_{2} \to C u_{2} S + 2 F e S + S O_{2}

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