The first diffraction minimum due to single slit diffraction is θ, for a light of wavelength 5000A. If the width of the sit is 1×10−4, then the value of θ is
A
300
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B
450
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C
600
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D
150
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Solution
The correct option is A300 dsinθ=nλ,n=11×10−6×sinθ=5000×10−10sinθ=12θ=30