The first electron acceptor in photosystem- I of the cyclic photophosphorylation is

Cytochrome.

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Plastocyanin.

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Ferredoxin.

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Plastoquinone.

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Solution

The correct option is C Ferredoxin.
During cyclic photophosphorylation, photosystem II is not involved. Only photosystem I is involved and ATP is synthesized alone. Reduced coenzyme $N A D P H_{2}$ are not produced. The electron acceptor in photosystem I is ferredoxin. In non cyclic electron flow, it passes on electrons to oxidised NADP but in cyclic electron flow it passes on electrons to cytochrome $b_{6}$ -f complex present in thylakoid membrane.

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Similar questions

Question 11
The correct sequence of flow of electrons in the light reaction is
(a) PS II, plastoquinone, cytochromes, PS I ferredoxin
(b) PS I, plastoquinone, cytochromes, PS II, ferredoxin
(c) PS I, ferredoxin, PS II
(d) PS I, plastoquinone, cytochromes, PS II, ferredoxin

Q. Find out the correct combination concerning the components of photosynthetic electron transport, location in relation to thylakoid and action.
(I) OEC - lumen side - water reduction
(II) Plastocyanin - lumen side - electron transfer from cytochrome f to PS I
(III) Ferredoxin - stroma side - reduction of NAD

^{+}

to NADH
(IV) Cytochrome complex - integral protein - transfer electrons from

P Q H_{2}

P C

The correct answer is

Q. Mention the photosystems and other components involved in non cyclic photophosphorylation.

Q. In noncyclic photophosphorylation, plastocyanin transfers electrons between

Q. Which is the last electron acceptor in cyclic photophosphorylation?

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