Question

The first four terms of an AP, whose first term is –2 and the common difference is –2, are

• A. – 2, – 4, – 8, –16
• B. – 2, – 4, – 6, – 8
• C. – 2, 0, 2, 4
• D. – 2, 4, – 8, 16

Answer 1

The correct option is B – 2, – 4, – 6, – 8

Given, the first term, $a=-2$ and the common difference, $d=-2$.
The first four terms of the AP will be $a,a+d,a+2d$ and $a+3d$.
Then the first four terms of the AP are:
$$\begin{array}{cc}& a,a+d,a+2d,a+3d\\ & =-2,-4,-6,-8,-10\end{array}$$