The first IE of lithium is 5-41eV and first electron affinity of Cl is 3-61eV- Calculate - H nearest integer value in kJ mol -1 for the reaction Lig-Clg-Li-g-Cl-g-Take nearest integer-

Δ H molecule of Li ^ + #160; Cl ^ = Li I E _ 1 + Cl E _ g a _ 1 #160;=5.41 3.61=1.80eV ∵ Li⟶ Li ^ + +e; I E _ 1 = ve and #1 ...

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Lattice Energy

The first I...

Question

The first $I E$ of lithium is $5.41 e V$ and first electron affinity of $C l$ is $3.61 e V$ . Calculate $Δ H$ (nearest integer value) in $k J {m o l}^{- 1}$ for the reaction
$L i (g) + C l (g) ⟶ {L i}^{+} (g) + {C l}^{-} (g)$
[Take nearest integer]

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5.41 e V

C l

- 3.61 e V

Δ H

k J

{m o l}^{- 1}

{L i}_{(g)} + {C l}_{(g)} \to {L i}_{(g)}^{+} + {C l}_{(g)}^{-}

5.4

C l

3.6

Δ H

L i_{(g)} + C l_{(} g) \to L i_{(g)}^{+} + C l_{(g)}^{-}

L i

C l

Δ H

k J m o l^{- 1}

L i_{(g)} + C l_{(g)} \to L i_{(g)}^{+} + C l_{(g)}^{-}

L i

5.4

C l

3.61

Δ H

L i (g) + C l (g) \to L i^{+} (g) + C l^{-} (g)

5.4

3.61

Δ

L i (g) + C l (g) \to L i^{+} (g) + C l^{-} (g)

1

= 1.6 \times 10^{- 19}

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