The first IE of Na, Mg and Si are respectively 496, 737, 786 KJ/mol. The IE of Al will be closer to

A) 760 KJ/mol. B) 575 KJ/mol. C) 801 KJ/mol. D) 419 KJ/mol.

Explain in detail.

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Solution

Na < Mg > Al < Si

The electronic configurations are as follows:

11Na(3s)1,12Mg(3s)2,13Al(3s)2(3p)1,14Si(3s)2(3p)211Na(3s)1,12Mg(3s)2,13Al(3s)2(3p)1,14Si(3s)2(3p)2

The ionization energy of Mg will be larger than that of Na due to fully filled configuration (3s)2(3s)2

The ionization of Al will be smaller than that of Mg due to one electron extra than the stable configuration but smaller than Si due to increase in effective nuclear charge of Si.

⇒⇒ Na < Mg > Al < Si

there the value of IE of Al will be closer to 760Kj/mol
option A

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The first IE of Na, Mg and Si are respectively 496, 737, 786 KJ/mol. The IE of Al will be closer to A) 760 KJ/mol. B) 575 KJ/mol. C) 801 KJ/mol. D) 419 KJ/mol. Explain in detail.

The first IE of Na, Mg and Si are respectively 496, 737, 786 KJ/mol. The IE of Al will be closer to

A) 760 KJ/mol. B) 575 KJ/mol. C) 801 KJ/mol. D) 419 KJ/mol.

Explain in detail.