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Question

The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be


A

-2.55 eV

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B

-5.1 eV

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C

-10.2 eV

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D

+2.55 eV

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Solution

The correct option is B

-5.1 eV


NaNa++e(FirstI.E)Na++eNa
Electron gain enthalpy of Na+ is reverse of (IE)
Because reaction is reverse so
ΔH (eq) =-5.1 eV


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