The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be
-2.55 eV
-5.1 eV
-10.2 eV
+2.55 eV
Na→Na++e−(FirstI.E)Na++e−→Na Electron gain enthalpy of Na+ is reverse of (IE) Because reaction is reverse so ΔH (eq) =-5.1 eV
The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be: