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Trend in Ionisation Enthalpy

The first ion...

Question

The first ionization energy for $N a$ is $495 k J / m o l$ .
The BEST estimate for sodium's second ionization energy would be

367 k J / m o l

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584 k J / m o l

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690 k J / m o l

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4560 k J / m o l

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Solution

The correct option is B $4560 k J / m o l$
After first ionization in Na, it attains inert gas configuration and because of that their is very high increase in ionization energy.
so, the estimated energy becomes $4560 K J / m o l$

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Similar questions

1060 k J / m o l

1005 k J / m o l

L i (g) ⟶ {L i}^{3 +} (g) + 3 e

1.96 \times 10^{4} k J

{m o l}^{- 1}

L i

520 k J

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L i

3635 \times x k J

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x

{I E}_{1}

H = 2.18 \times 10^{- 18} k J

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B e

899 k J / m o l

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N a

107 k J / m o l

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- 355 k J / m o l

△ H_{f}^{0}

- 411 k J / m o l

Element	First Ionization Energy (kJ/mol)
Lithium	520
Sodium	496
Rubidium	403
Cesium	376

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