The first ionization energy (in kJ/mol) of Na, Mg, Al and Si, respectively, are:
A
496,737,577,786
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B
496,577,737,786
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C
496,577,786,737
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D
786,737,577,496
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Solution
The correct option is A496,737,577,786 The expected order is Na<Mg<Al<Si But the actual/experimental order turns out to be Na<Al<Mg<Si because of the fully filled s-subshell of magnesium and the s2p1 configuration of Al which makes it relatively easy for Al to lose its outermost electron.