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Question

The first ionization energy of Na, NO, Xe, and O2 follows the order Na<NO<Xe=O2.O2 reacts with the powerful oxidizing agent PtF6 to yield a compound O2[PtF6].

When PtF6 is allowed to react with other mentioned species, then the product is :

A
Na[PtF6]
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B
NO[PtF6]
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C
Xe[PtF6]
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D
All of the above
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Solution

The correct option is D All of the above
Since the ionization energy of oxygen is the maximum and [PtF6] is able to take an electron out of it, it means that all the other species having lower potentials should easily give away electrons to form a complex.

Hence, Na[PtF6], NO[PtF6], Xe[PtF6] are formed.

So, the correct option is D

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