Question

The first ionization potential of four consecutive elements in the second period of the periodic table is $8.3$, $11.3$, $14.5$, and $13.6$ eV respectively. Which one of the following is the first ionization potential of carbon?

• A. $13.6$
• B. $11.3$
• C. $8.3$
• D. $14.5$

Answer 1

The correct option is B $11.3$

The first ionization potential of carbon is $11.3eV$.
The four consecutive elements are $B,C,N$ and $O$.

We know that the first ionization potential of $N$ is higher than the first ionization potential of $O$ as in the case of $N$, the electron is to be removed from stable half-filled $2p$ orbital.

Hence, option B is correct.