The first ionization potential values of $N a, M g, A l$ and $S i$ atoms will be in the order of :

N a < M g > A l < S i

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N a > M g < A l > S i

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N a < M g > A l > S i

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N a > M g > A l < S i

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Solution

The correct option is A $N a < M g > A l < S i$
$N a, M g, A l$ and $S i$ belongs to third period. First ionization potential increases across period from left to right. But I.P of magnesium is greater than sodium because of the fully filled configuration of magnesium. On the other hand, aluminium looses one one electron to get stable magnesium configuration, hence I.P of $A l$ is less than $S i$ . The correct order is $M g < N a < S i < A l$ .

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The first ionization potential values of Na, Mg, Al and Si atoms will be in the order of :

The first ionization potential values of $N a, M g, A l$ and $S i$ atoms will be in the order of :