The first ionization potentials (in eV) of $A s$ and $S e$ atoms, respectively, are:

14.6, 13.6

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13.6, 14, 14.6

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13.6, 13.6

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14.6, 14.6

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Solution

The correct option is B $14.6, 13.6$
$A s$ have half filled configuration so it will have higher $I P$ than $S e .$
$A s = 14.6$
$S e = 13.6$

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The first ionization potentials (in eV) of As and Se atoms, respectively, are:

The correct option is B 14.6,13.6As have half filled configuration so it will have higher IP than Se.As=14.6Se=13.6

The first ionization potentials (in eV) of $A s$ and $S e$ atoms, respectively, are:

The correct option is B $14.6, 13.6$
$A s$ have half filled configuration so it will have higher $I P$ than $S e .$
$A s = 14.6$
$S e = 13.6$