Question 29
The first member of alkyne homologous series is
(a) ethyne
(b) ethene
(c) propyne
(d) methane

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Solution

The answer is (a).

Ethyne is the first member of alkyne homologous series. Its structure is given below:

$H-C \equiv C-H$

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Write the molecular formula of the $2^{n} d$ and $3 n d$ member of the homologous series whose first member is methane.

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