The first order diffraction of X-rays from a certain set of crystal planes occur at an angle of 11-8- from the planes- If the planes are 281 pm apart- what is the wavelength of X-rays sin 11-8-0-2045A- 115 pmB- 125 pmC- 135 pmD- 97-5 pm

The correct option is A 115 pm nλ = 2d sin θ λ =2 × 281 × 10^ 12× 0.2045/1=115 × 10^ 12m=115pm ...

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Standard XII

Physics

Optical Fiber

The first ord...

Question

The first order diffraction of X-rays from a certain set of crystal planes occur at an angle of ${11.8}^{\circ}$ from the planes. If the planes are 281 pm apart, what is the wavelength of X-rays (sin ${11.8}^{\circ}$ = 0.2045)

115 pm

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125 pm

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135 pm

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97.5 pm

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Solution

The correct option is A 115 pm
$n λ = 2 d s i n θ λ = \frac{2 \times 281 \times 10^{- 12} \times 0.2045}{1} = 115 \times 10^{- 12} m = 115 p m$

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The first order diffraction of X-rays from a certain set of crystal planes occur at an angle of 11.8∘ from the planes. If the planes are 281 pm apart, what is the wavelength of X-rays (sin 11.8∘ = 0.2045)

The correct option is A 115 pm nλ=2d sin θλ=2×281×10−12×0.20451=115×10−12m=115pm

The first order diffraction of X-rays from a certain set of crystal planes occur at an angle of ${11.8}^{\circ}$ from the planes. If the planes are 281 pm apart, what is the wavelength of X-rays (sin ${11.8}^{\circ}$ = 0.2045)

The correct option is A 115 pm
$n λ = 2 d s i n θ λ = \frac{2 \times 281 \times 10^{- 12} \times 0.2045}{1} = 115 \times 10^{- 12} m = 115 p m$