The first order diffraction of X- rays from a certain set of crystal planes occurs at an angle of ${11.8}^{o}$ from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is $(s i n {11.8}^{o} = 0.2045)$

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Solution

According to bragg's Law
$n λ = d sin θ$
Since layers are consecutive,
$∴$ taking $n = 1$
$λ = (0.2) (sin {11.8}^{o})$
$= (0.2) (0.2045)$
$= 0.0409 n m$
$λ = 0.409 ˚ A$

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The first order diffraction of X- rays from a certain set of crystal planes occurs at an angle of 11.8o from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is (sin11.8o=0.2045)

According to bragg's Lawnλ=dsinθSince layers are consecutive,∴ taking n=1λ=(0.2)(sin11.8o)=(0.2)(0.2045)=0.0409 nmλ=0.409 ˚A

The first order diffraction of X- rays from a certain set of crystal planes occurs at an angle of ${11.8}^{o}$ from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is $(s i n {11.8}^{o} = 0.2045)$

According to bragg's Law
$n λ = d sin θ$
Since layers are consecutive,
$∴$ taking $n = 1$
$λ = (0.2) (sin {11.8}^{o})$
$= (0.2) (0.2045)$
$= 0.0409 n m$
$λ = 0.409 ˚ A$