Question

The first order rate constant for dissociation of $N_2{O}_5$ is $6.2\times {10}^{-4}{s}^{-1}$. The half-life period (in $s$) of this dissociation will be.

• A. $1117.7$
• B. $111.7$
• C. $223.4$
• D. $160.9$

Answer 1

Answer: (A)

$1117.7$

$t_{1/2}=\frac{0.693}{k}$

$=\frac{0.693}{6.2\times {10}^{-4}}=1117.7s$