Question

The first overtone of an open pipe has frequency n . The first overtone of a closed pipe of the same length will have frequency

• A. $\frac{n}{2}$
• B. 2n
• C. $\frac{3n}{4}$
• D. $\frac{4n}{3}$

Answer 1

The correct option is C $\frac{3n}{4}$

First overtone of an open pipe frequency, $2{\nu }_0=\frac{2\nu }{2L}=n$ -----(1)

First overtone of an closed pipe have frequency, $3{\nu }_c=\frac{2\nu }{4L}$ -----(2)

So, from $\frac{\nu }{L}=n$

=> $\frac{3\nu }{4L}=\frac{3n}{4}$