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Standard XII

Chemistry

Distinguishing Test of Terminal and Non Terminal Alkynes

the first que...

Question

the first question
Q. A hydrocarbon Y decolorizes bromine water. On ozonolysis it gives 3-methyl butanal and formaldehyde. Give the name and formula of the compound with the respective ozonolysis reaction.
(ii) Write one reaction to show the acidic nature of ethyne.
(iii) State Markovnicoff's rule. Using this write the reaction of propene with HCl

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Solution

$C H_{3} C H (C H_{3}) C H_{2} C H = C H_{2} + O_{3} \to C H_{3} C H (C H_{3}) C H_{2} C H O + H C H O 4 - m e t h y l p e n t - 1 - e n e 3 - m e t h y l b u t a n a l$
Hence, in the above reaction shows that Hydrocarbon Y is 4-methylpent-1-ene , (formula = CH₃CH(CH₃)CH₂CH=CH₂) which on ozonolysis (O₃) gives 3-methyl butanal ,CH₃CH(CH₃)CH₂CHO and formaldehyde, HCHO.

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CH3CH(CH3)CH2CH = CH2 + O3 →CH3CH(CH3)CH2CHO + HCHO 4-methyl pent-1-ene 3- methyl butanal Hence, in the above reaction shows that Hydrocarbon Y is 4-methylpent-1-ene , (formula = CH3CH(CH3)CH2CH=CH2) which on ozonolysis (O3) gives 3-methyl butanal ,CH3CH(CH3)CH2CHO and formaldehyde, HCHO.