wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

the first question
Q. A hydrocarbon Y decolorizes bromine water. On ozonolysis it gives 3-methyl butanal and formaldehyde. Give the name and formula of the compound with the respective ozonolysis reaction.
(ii) Write one reaction to show the acidic nature of ethyne.
(iii) State Markovnicoff's rule. Using this write the reaction of propene with HCl

Open in App
Solution


CH3CH(CH3)CH2CH = CH2 + O3 CH3CH(CH3)CH2CHO + HCHO 4-methyl pent-1-ene 3- methyl butanal
Hence, in the above reaction shows that Hydrocarbon Y is 4-methylpent-1-ene , (formula = CH3CH(CH3)CH2CH=CH2) which on ozonolysis (O3) gives 3-methyl butanal ,CH3CH(CH3)CH2CHO and formaldehyde, HCHO.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Alkynes - Chemical Properties
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon