MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Multi-Electron Configurations and Orbital Diagrams

The first, se...

Question

The first, second and third ionisation energies of Al are 578, 1817 and 2745 kJ mol^{-1} respectively. Calculate the energy required to convert all the atoms of Al to Al^{+3} present in 270 mg of Al vapours 1)51.40k

Open in App

Solution

Suggest Corrections

thumbs-up

32

Similar questions

Q. The first, second and third ionisation energies of

A l

578, 1817

2745

m o l^{- 1}

respectively. Calculate the energy required to convert all the atoms of

A l

A l^{+ 3}

270

A l

Q. The I. II and III I.E. of al are 578, 1817 and 2745 kJ/mol

^{- 1}

respectively. Calculate the energy required to convert all the atoms of Al to Al

^{3 -}

present in 270 mg of Al vapours.

Q. The first ionisation energies of six

3^{r d}

period elements are 496, 578, 738, 789, 1000 and 1012

{kJ mol}^{- 1}

. The elements to which these energies correspond respectively are:

Q. Ionisation energy of

A l t o A l^{3 +} = 5137 k J m o l^{- 1} △ H_{h y d r a t i o n} o f : A l^{3 +} = - 4665 k J m o l^{- 1} a n d f o r C l^{-} = - 381 k J m o l^{- 1} .

Which of the following statement is correct?

Q. The first ionization energy (in kJ/mol) of

N a, M g, A l

S i

respectively, are

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electronic Configuration and Orbital Diagrams

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Multi-Electron Configurations and Orbital Diagrams

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon