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Mass Energy Equivalence

The first, se...

Question

The first, second and third ionisation energies of Alare 578, 1817 and 2745 kJ mol-1 respectively.Calculate the energy required to convert all the atomsof Al to Al+3 present in 270 mg of Al vapours(1) 5140 kJ(2) 51.40 kJ(3) 2745 kJ(4) 514.0 kJ

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Similar questions

A l

578, 1817

2745

m o l^{- 1}

A l

A l^{+ 3}

270

A l

^{- 1}

^{3 -}

A l t o A l^{3 +} = 5137 k J m o l^{- 1} △ H_{h y d r a t i o n} o f : A l^{3 +} = - 4665 k J m o l^{- 1} a n d f o r C l^{-} = - 381 k J m o l^{- 1} .

I E

A l (g) ⟶ {A l}^{+} (g) + e

577.5 k J

{m o l}^{- 1}

Δ H

A l (g) ⟶ {A l}^{3 +} (g) + 3 e

5140 k J

{m o l}^{- 1}

I E

2 : 3

{I E}_{2}

{I E}_{3} - 0.5

k J

{m o l}^{- 1}

3^{r d}

{kJ mol}^{- 1}

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