The first, second, third and fourth, ionization potential values of an element are $8.3, 25.15, 37.92$ and $259.3$ eV respectively. The element is:

magnesium

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silicon

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sodium

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aluminium

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Solution

The correct option is D aluminium
There is a large difference between the third and fourth ionization potential of the given element . Therefore the given element should have three valence electrons. Among the above options $A l$ satisfies this condition.

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