The first term $a$ and common difference $d$ are given . Find first four terms of A.P. $a = 3, d$ = 4

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Solution

$a = 3, d = 4$

$∴$ First term $= t_{1} = a = 3$

Second term $= t_{2} = a + d = 3 + 4 = 7$

Third term $= t_{3} = a + 2 d = 3 + 2 \times 4 = 3 + 8 = 11$

Fourth term $= t_{4} = a + 3 d = 3 + 3 \times 4 = 3 + 12 = 15$

$∴$ the four terms of A.P are $3, 7, 11, 15$

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The first term a and common difference d are given . Find first four terms of A.P. a=3,d = 4

a=3,d=4∴ First term=t1=a=3Second term=t2=a+d=3+4=7Third term=t3=a+2d=3+2×4=3+8=11Fourth term=t4=a+3d=3+3×4=3+12=15∴ the four terms of A.P are 3,7,11,15

The first term $a$ and common difference $d$ are given . Find first four terms of A.P. $a = 3, d$ = 4

$a = 3, d = 4$

$∴$ First term $= t_{1} = a = 3$

Second term $= t_{2} = a + d = 3 + 4 = 7$

Third term $= t_{3} = a + 2 d = 3 + 2 \times 4 = 3 + 8 = 11$

Fourth term $= t_{4} = a + 3 d = 3 + 3 \times 4 = 3 + 12 = 15$

$∴$ the four terms of A.P are $3, 7, 11, 15$