The first term and $15^{t h}$ term of an AP are 7 and 35 respectively. Find the common difference.

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-2

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2.5

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Solution

The correct option is B
2

$n^{t h}$ term in an AP is given by $a_{n} = a + (n - 1) d$

Given $a_{15}$ = 35 and a = 7

Hence,
$a_{15} = 7 + (15 - 1) d$

35 = 7 + 14d

28 = 14 d

d = 2

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